## Friday, March 21, 2008

### Homework 5

Sorry for the delay, HW5 is up on the web page.

#### 3 comments:

Jeremiah said...

For 3.a is this supposed to be $f:{-1,1}^n\rightarrow\mathbb{R}$ or is it $f:{-1,1}^n\rightarrow{-1,1}$ as stated?

Jeremiah said...

Whoops, I meant
$f:\{-1,1\}^n\rightarrow\mathbb{R}$ or is it $f:\{-1,1\}^n\rightarrow\{-1,1\}$

Anupam said...

I think it is supposed to be $f:\{-1,1\}^n\rightarrow\{-1,1\}$.